Construct a ∆ ABC such that AB = AC = 5.5 cm and m LBAC = 60°
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Answer:
1. Draw a line AC=5 cm.
2. Construct ∠A=60
∘
and mark it as Y.
3. Cut off line segment AD=1.2 cm on AY.
4. Join C−D.
5. Draw a perpendicular bisector of CD such that it intersects AY at B.
6. Join B−C.
7. ABC is the required triangle.
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