Question

Construct a ∆ ABC where AB = 4.5 cm, BC = 5.8 cm and Angle AC = 5.2cm using compass and ruler. Write working steps.​

Answer 1

Answer:

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Class 9

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>>Construction of Triangles

>>Construct a triangle ABC in which AB = 5

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Construct a triangle ABC in which AB=5.8 cm,BC+CA=8.4 cm and ∠B=60

∘

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Solution

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Steps of construction

1. Draw a line segment AB of length 5.8cm.

2. Draw a line segment BX, sufficiently large such that ∠ABX=60

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.

3. From the segment BX, cut off line segment BD of length 8.4cm.

4. Join AD.

5. Draw the perpendicular bisector of AD and let it meet BD at C.

6. Join AC.

Then ABC is the required triangle.

Answer 2

Step-by-step explanation:

I haven't construct it but I'll tell you the steps how to construct it...

step 1: draw a line AB of 4.5cm

step 2: take a compass and put it's centre on B

and take 5.8 cm length in compass and make an arc

step 3: now put the compass on the point A and take 5.2cm length in compass and make an arc on side where you had made the length of 5.8 cmand the point where the points cut each other is point C then joint all the points.

you're triangle is constructed...