Construct a ΔABC with BC = 6 cm, AB = 5.2 cm and AC = 6.3 cm.
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Step-by-step explanation:
Step of construction of your question is:-
(1) Draw a line segment BC = 6 cm
(2) With B as center and radius equal to 5.2 cm draw an arc.
(3) Then C as center and radius equal to 4.8 cm, draw another arc, which cutting the previous arc at a point A.
(4) Then Join AB and AC.
Then, ∆ABC is the required triangle. In which AB = 5.2 cm , BC = 6 cm and AC = 4.8 cm
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