Construct a angle ABC in which be = 6.5cm angle b = 60ab +AC = 10cm
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Triangle construction:
1. Draw a horizontal line BD with a ruler.
2. Mark B on it. With a compass draw an arc of radius 6.5 cm to cut BD at C.
3. Draw a line BE inclined at an angle of 60 deg. with BC, at B.
Follow the procedure to draw 60 deg angle line. Or, draw it using
a protractor.
4. Draw an arc with center as B and a radius = 10 cm to cut the line BE
at point F.
5. Join FC. Draw a perpendicular bisector GH of FC.
6. Intersection of GH and BF is the point A.
7. Join AC to complete the triangle ABC.
1. Draw a horizontal line BD with a ruler.
2. Mark B on it. With a compass draw an arc of radius 6.5 cm to cut BD at C.
3. Draw a line BE inclined at an angle of 60 deg. with BC, at B.
Follow the procedure to draw 60 deg angle line. Or, draw it using
a protractor.
4. Draw an arc with center as B and a radius = 10 cm to cut the line BE
at point F.
5. Join FC. Draw a perpendicular bisector GH of FC.
6. Intersection of GH and BF is the point A.
7. Join AC to complete the triangle ABC.
kvnmurty:
:-)
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