Question

Construct a angle PQR, if PQ = 4 cm, PR = 4.6 cm and angle P = 72°​

Answer 1

Answer:

my dear friend your answer is

Step-by-step explanation:

Steps of Construction:

(i) Draw a line segment that is sufficiently long using a ruler.

(ii) Locate points Q and R on it such that QR=5.2cm.

(iii) At Q, construct a line segment QM, sufficiently large, such that ∠MQR at 60

∘

use protractor to measure 60

∘

(iv) With Q as centre and radius 4cm, draw the line cutting QM at P, join PR.

Then PQR is the required triangle.

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