construct a ∆, angle Q=105°,angle R=30° and ∆PQR=12.5cm?
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1) Draw a base of 12.5 cm.
2) Draw bisectors of the angles given.Here,you need to draw 105°/2 = 52.5° and 30°/2 =15° from the ends of the segment.
3) Elongate them till they meet at a point. Say, this point is R.
4) Draw perpendicular bisectors for both the sides.
5) Elongate both the perpendicular bisectors till they meet at the base. These are points P and Q.
6) Join P and Q to R.
7) ∆PQR is complete.
Yay! We completed the construction.Recheck it by measuring the angles and the perimeter.
2) Draw bisectors of the angles given.Here,you need to draw 105°/2 = 52.5° and 30°/2 =15° from the ends of the segment.
3) Elongate them till they meet at a point. Say, this point is R.
4) Draw perpendicular bisectors for both the sides.
5) Elongate both the perpendicular bisectors till they meet at the base. These are points P and Q.
6) Join P and Q to R.
7) ∆PQR is complete.
Yay! We completed the construction.Recheck it by measuring the angles and the perimeter.
Answered by
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1-draw ab=12.5cm
2-at A construct 105°
3-at B construct 30°
4-draw the angle bisector of angle a&b
5-extend the line as ax and by(mark the meeeting point as p)
6-draw the perpendicular bisector of AX and BY
7-mark the point where perpendicular bisectors of AX and BY as q and r
8-join PQR
9- pq+qr+pr=12.5cm
10-pqr is the required triangle
2-at A construct 105°
3-at B construct 30°
4-draw the angle bisector of angle a&b
5-extend the line as ax and by(mark the meeeting point as p)
6-draw the perpendicular bisector of AX and BY
7-mark the point where perpendicular bisectors of AX and BY as q and r
8-join PQR
9- pq+qr+pr=12.5cm
10-pqr is the required triangle
nesthangam:
we dont need to write something as it is from the book
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