Construct a angleABC with your own measurements. Construct another triangle similar to angelABC, with its sides equal to 5/3of the corresponding sides of the triangle ABC.
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corresponding sides are 15sum is 180
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This is a very good question.
Draw the triangle ABC as desired by your choice.
Draw a line AD. Step out arc with centre at A to cut the line AD at D1. From D1 Step out another arc with same radius to cut AD at D2. Similarly D3,D4, D5.Join D3 to C. Draw a line parallel to D3C from D5 to cut AC extended at say C’.
Join D3B. Through D5 draw a line parallel to D3B to cut AB extended at say B’. Join B’and C’.
The triangle formed by the points AB’C’ will be the required triangle.
Draw the triangle ABC as desired by your choice.
Draw a line AD. Step out arc with centre at A to cut the line AD at D1. From D1 Step out another arc with same radius to cut AD at D2. Similarly D3,D4, D5.Join D3 to C. Draw a line parallel to D3C from D5 to cut AC extended at say C’.
Join D3B. Through D5 draw a line parallel to D3B to cut AB extended at say B’. Join B’and C’.
The triangle formed by the points AB’C’ will be the required triangle.
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