Question

construct a dihybrid cross where pure round and green pea seeds are crossed with pure wrinkled and yellow seeds upto the f2 generation. also write the phenotypic ratio in both the generations.​

Answer 1

Answer:

A cross is made between homozygous yellow round seeds(YYRR) to another homozygous green wrinkled seeds(yyrr). In the F1 generation, all plants are heterozygous yellow round(YyrRr). When this plant is subjected to self pollination, in the F2 generation, 9 plants are Yellow round, 3 plants are yellow wrinkled, 3 plants are green round and 1 plant is green wrinkled are formed.

The dihybrid phenotypic ratio is 9:3:3:1.

So, the correct option is ‘9:3:3:1’.

Answer 2

Answer:

The Genotypic ratio is 1:2:1:2:4:2:1:2:1 and the phenotypic ratio is 9:3:3:1