Construct a equilateral if one of its altitudes is length 4.5 cm
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*Draw a line PQ.
*Take any point L on this line.
*Construct perpendicular AL on PQ.
Cut a line segment AD from D equal to 4.5 cm.
*Make angles equal to 30° at A on both sides of AD, say ∠CAD and ∠BAD where B and C lie on XY.
*Then, ABC is the required triangle.
Justification:
*Since ∠A = 30° + 30° = 60° and AL ⊥ BC,
*Take any point L on this line.
*Construct perpendicular AL on PQ.
Cut a line segment AD from D equal to 4.5 cm.
*Make angles equal to 30° at A on both sides of AD, say ∠CAD and ∠BAD where B and C lie on XY.
*Then, ABC is the required triangle.
Justification:
*Since ∠A = 30° + 30° = 60° and AL ⊥ BC,
swettiii:
plzz send the fig also
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