Question

construct a equilateral triangle of altitude 6.5 cm

Answer 1

(1) Take a base AB of length, let's take 6 cm.......... (2) Draw perpendicular bisector of AB and wherever it meets on AB, name that point O....... (3) Open the compass for 6.5 cm , keep the pointer at O and draw an arc s.t. it cuts the perpendicular bisector. Name that point C............(4) Join AC and BC........... ABC is the required ∆.

Answer 2

Step-by-step explanation:

Take a base AB of length let's take 6 cm.....

Draw a perpendicular bisector of AB and wherever it meets on AB name the point O......

Open the compass for 6.5cm keep the pointer at O and draw an arc s.t it cuts the perpendicular bisector .....

Name the point C.....

join AC and BC...

THUS, ABC IS THE REQUIRED TRIANGLE....