Construct a equillatral triangle p q r each side 5cm.
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1. make sode qr of 5cm
2. take geometry compass(rounder) and set 5cm and make arc.
3. then from other point (r) take compass and make arc of 5cm
4. then two arc intersect join pointq to arc and point r to arc
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Answer:
Step-by-step explanation:
Let ABC be the ∆ ...... (1)Draw AB as base = 5 cm......... (2) Draw perpendicular bisector of AB....... (3) Open the compass for 5 cm, keep the pointer at A and draw an arc such that it cuts the bisector........ (4) Do the same with point B and wherever those arcs meet name that point C......... (5) Thus ABC is the required ∆.
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