Construct a line through Q which parallel to X and Y
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Step-by-step explanation:
The point P=(p,q)=(3,4) and a line is drawn parallel to Y-axis.
Therefore, th equation of the line is x=p=3
Again another line is drawn parallel to X-axis through a point Q=(r,s)=(1,−7)
Therefore, the equation of the line is y=s=−7
Therefore, the lines are x=3 and y=−7
Therefore, the point of intersection is
(x,y)=(3,−7)
Answered by
0
Step-by-step explanation:
The point P=(p,q)=(3,4) and a line is drawn parallel to Y-axis.
Therefore, th equation of the line is x=p=3
Again another line is drawn parallel to X-axis through a point Q=(r,s)=(1,−7)
Therefore, the equation of the line is y=s=−7
Therefore, the lines are x=3 and y=−7
Therefore, the point of intersection is
(x,y)=(3,−7)
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