Question

construct a parallel line to a line AB from distance 4.7cm​

Answer 1

Answer:

Steps for construction,

1. Draw a line AB.

2. Take any two points P and Q on AB.

3. Construct angle BPE = angle BQF= 90

o

4. With P as center and radius equal to 3.5cm, cut PE at R.

5. With Q as center and radius equal to 3.5cm, cut QF at S.

6. Join CD and produce it on either side to get the required line CD parallel to AB and at a distance of 3cm from it.