Question

construct a parallelogram ABCD ab = 6cm BC =3.8 cm angle A= 110 degree​

Answer 1

Step-by-step explanation:Draw a line segment AB = 6cm.⇒ Construct an angle of 60 ∘ at point B.⇒ Cut off BC = 4cm.⇒ We know that adjacent angles of parallelogram are supplementary then, construct an angle of 120 ∘ at point A and C which meet at point D.⇒ Thus, ABCD is a required parallelogram.⇒ Let AB=a=6cm and BC=b=4cm --- ( 1 )⇒ Perimeter of parallelogram ABCD=2(a+b)⇒ 2(6+4) [From( 1 )]∴ Perimeter of parallelogram ABCD=20cm.

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Answer 2

Step-by-step explanation:

Take AB = 6 cm. At A make angle of 110 degree by protector and take AD = 3.8 cm. Now extend AD to point E. Draw a line making a clockwise angle of 110 degree with AE at D. Mark point C at a distance of 6 cm from D. Join CB. Now our parallelogram is complete.