Construct a parallelogram ABCD, GIVEN THAT BD=6cm, AC= 7cm, and the angle included between the diagonals is 30 degree.
Pls explain step by step and the one who gives the proper answer first will be marked as the brainliest.
Answers
Answer:
We assume that the pages start from 1.
A one-digit number is greater or equal to 1 and less than 10.
\implies10-1=9⟹10−1=9
There are 9 possible one-digit numbers.
A two-digit number is greater or equal to 10 and less than 100.
\implies100-10=90⟹100−10=90
There are 90 possible two-digit numbers.
A three-digit number is greater or equal to 100 and less than 1000. However, we have 456 at the last page.
\implies456-100=356⟹456−100=356
Then we have 356 possible three-digit numbers.
The total digit will be the sum of
\rightarrow\text{The number of one-digit number}\times1→The number of one-digit number×1
\rightarrow\text{The number of two-digit number}\times2→The number of two-digit number×2
\rightarrow\text{The number of three-digit number}\times3→The number of three-digit number×3
\text{(Total number of digits)}(Total number of digits)
=9\times1+90\times2+356\times3=9×1+90×2+356×3
=9+180+1068=9+180+1068
=1257=1257
\large\underline{\text{Answer}}
Answer
None of the above is correct
Step-by-step explanation:
We assume that the pages start from 1.
A one-digit number is greater or equal to 1 and less than 10.
\implies10-1=9⟹10−1=9
There are 9 possible one-digit numbers.
A two-digit number is greater or equal to 10 and less than 100.
\implies100-10=90⟹100−10=90
There are 90 possible two-digit numbers.
A three-digit number is greater or equal to 100 and less than 1000. However, we have 456 at the last page.
\implies456-100=356⟹456−100=356
Then we have 356 possible three-digit numbers.
The total digit will be the sum of
\rightarrow\text{The number of one-digit number}\times1→The number of one-digit number×1
\rightarrow\text{The number of two-digit number}\times2→The number of two-digit number×2
\rightarrow\text{The number of three-digit number}\times3→The number of three-digit number×3
\text{(Total number of digits)}(Total number of digits)
=9\times1+90\times2+356\times3=9×1+90×2+356×3
=9+180+1068=9+180+1068
=1257=1257
\large\underline{\text{Answer}}
Answer
None of the above is correct