Question

Construct a parallelogram ABCD in which AB=5cm, AC=7cm, and BD= 6cm.​

Answer 1

Answer:

your answer is this

Step-by-step explanation:

⇒ Draw a line segment AB = 5cm.

⇒ With A as a center and radius AC = 5cm, draw an arc.

⇒ With B as a center and radius BC = 6cm, draw an arc, intersecting the previous arc at point C.

⇒ With A as a center and radius AD = 3cm, draw an arc.

⇒ Take C as a center with radius CD = 4cm draw an arc intersecting the previous arc at point D.

⇒ Join AC, BC, AD and CD.

Thus, ABCD is a required quadrilateral.

solution

Answers verify by Ishika

Answer 2

Steps of Construction:

1. Draw a line segment AB of length 5 cm.

2. With A as the center, draw an arc of ½ AC = 3.5 cm.

3. With B as the center, draw an arc of of radius ½ BD = 3cm to intersect the arc drawn in step 2 at O.

4. Join O to A and B.

5. Produce AO and cut off OC = OA = 3.5 cm.

6. Produce BO and cutoff OD = OB = 3 cm.

7. Join D and A; D and C; and C and B.

ABCD is the required parallelogram.