construct a parallelogram ABCD in which AB=6 cm,<A=60° and BC=5cm
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Draw AB = 6 cm.
At A draw ∠QAB = 60°.
From AQ cut AD = 3 cm.
From D, draw an arc of radius 6 cm.
From B, draw an arc of radius 3 cm which meets first arc at C.
Join CD and BC. Thus ABCD is the required ||gm.
Bisect ∠DAB, so that bisector meets CD at P.
Join PB and measure ZAPB. ∴ ∠APB = 90°.
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