Question

Construct a parallelogram ABCD,in which AB=6cm,BC=5cm,∆B =70° and ∆A=60°

Answer 1

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Answer 2

$ABCD$ is the required parallelogram.

Step-by-step explanation:

Given,

Construct a parallelogram $ABCD$ where $AB=6\ cm,BC=5\ cm,\angle B =120\ degree\ and\ \angle A=60\ degree$

Following steps:

• Draw a line segments $AB=6\ cm$ using scale.
• At $A$, draw an angle $60\ degree$ using protector like $\angle BAX=60\ degree$
• At $B$, draw an outside angle $70\ degree$ using protector like $\angle ABY=120\ degree$

• Take $B$ as center and $5\ cm$ as radius, draw an arc $C$ on line $BY$

• Take $C$ as center and $6\ cm$ as radius, draw an arc $D$ on line $AX$

• Join $CD$

Hence, $ABCD$ is the required parallelogram.