construct a parallelogram ABCD in which ab sports and BC 5 cm and angle b is 60 degree
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B
20 cm
⇒ Draw a line segment AB = 6cm.
⇒ Construct an angle of 60
∘
at point B.
⇒ Cut off BC = 4cm.
⇒ We know that adjacent angles of parallelogram are supplementary then, construct an angle of 120
∘
at point A and C which meet at point D.
⇒ Thus, ABCD is a required parallelogram.
⇒ Let AB=a=6cm and BC=b=4cm --- ( 1 )
⇒ Perimeter of parallelogram ABCD=2(a+b)
⇒ 2(6+4) [From( 1 )]
∴ Perimeter of parallelogram ABCD=20cm.
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