Construct a parallelogram abcd in which ac =6cm ,bd=8cm and angle between the diagonal is 75degress
Answers
Steps of construction:
1. Draw a linesegment BD of 8cm.
2. Draw perpendicular bisector of the linesegment BD.
3. To draw perpendicular bisector, take your compass and set its radius as more than half of the linesegment BD. You can set the radius of 5cm to draw the perpendicular bisector for this question. After maintaining the radius , put the compass needle on point B and cut arcs on both sides of linesegment BD. Then keep the compass needle on point D and follow the same method as for point B.
You will observe that the arcs intersect each other . Join both of points of intersection using a dotted line . Your perpendicular bisector us ready .
4. Keep the protactor on linesegment BD where the perpendicular bisector cuts the line .
5. Draw 75° on both sides and join them.
6 . Take a radius of 3cm and cut arcs on
75° slanting line on both sides .
7. Label them as A and C.
8. Join the points A,B,C and D .
9. Your quadrilateral is ready.
10. To verify , measure BD and AC . You will observe BD as 8cm and AC as 6cm.
Hope it helps.
Please make it the Branliest Answer.
Step-by-step explanation:
- your mother I m world idiot come have with me my boy