Question

Construct a parallelogram ABCD, in which diagonal AC = 3.8 cm, diagonal BD = 4.6 cm and the angle between AC and BD is 60°.

Answer 1

Answer:

Step1: Draw a line AC= 3.8cm Step2:Bisect AC at O. Step3: At O draw ∠COX= 60o Step4: Set the value OB= 2.3cm and OD=2.3cm (divided the value 4.6 into 2.3 and 2.3) Step5: Now join AB,BC,CD,DARead more on Sarthaks.com - https://www.sarthaks.com/739354/construct-parallelogram-abcd-which-diagonal-8cm-diagonal-6cm-and-the-angle-between-and-60

Answer 2

Step-by-step explanation:

The given Parallelogram ABCD can be drawn by following the steps.

Step 1: Draw a line AC=3.8cm

Step 2: Bisect AC at O.

Step 3: At O draw ∠COX=60°

Step 4: Set the value OB=2.3cm and OD=2.3cm (divided the value 4.6 into 2.3 and 2.3)

Step 5: Now join AB,BC,CD,DA

We get the required parallelogram ABCD

solution