construct a parallelogram ABCD,in which diagonal AC=3.8cm diagonal BD=4.6cm and the angle between AC and BD is 120°
Please draw in copy please
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Answer:
The given Parallelogram ABCD can be drawn by following the steps.
Step1: Draw a line AC= 3.8cm
Step2:Bisect AC at O.
Step3: At O draw ∠COX= 60°
Step4: Set the value OB= 2.3cm and OD=2.3cm (divided the value 4.6 into 2.3 and 2.3)
Step5: Now join AB,BC,CD,DA
∴ The constructed parallelogram looks like:
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please answer me too
Step-by-step explanation:
I have a doubt..sorry
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