Math, asked by drjavaid354, 1 month ago

construct a parallelogram " ABCD in which mAB is equal to 4 cm and BC is equal to 3 cm and angle b is equal to 60 degree"​

Answers

Answered by dee0408
1

Step-by-step explanation:

Draw a line segment AB = 6cm.

⇒  Construct an angle of 60∘ at point B.

⇒  Cut off BC = 4cm.

⇒  We know that adjacent angles of parallelogram are supplementary then, construct an angle of 120∘ at point A and C which meet at point D.

⇒  Thus, ABCD is a required parallelogram.

⇒  Let AB=a=6cm  and BC=b=4cm    --- ( 1 )

⇒  Perimeter of parallelogram ABCD=2(a+b)

⇒   2(6+4)                                 [From( 1 )]

∴   Perimeter of parallelogram ABCD=20cm.

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