Question

Construct a parallelogram ABCD in which side
BC = 5.6 cm and diagonals AC = 6.2 cm and
BD = 8 cm​

Answer 1

Answer:

Step-by-step explanation:

Let AC and BD are the diagonal of the parallelogram which intersects each other at point O.

Now, AO = OC = AC/2 = 6.2/2 = 3.1

And BO = OD = BD/2 = 8/2 = 4

Construction:

1. Draw a line segment BC of length 5.6 cm

2. Now, take B as center and draw an arc length of 4 cm

3. Again, take C as center and draw an arc length of 3.1 cm which intersect the previous arc at point O

4. Now, join O to B and C

5. Extend BO to D such that BD = 8

6. Extend CO to A such that AC = 6.2

7. Finally, join A to B, A to D and C to D.

This is the required parallelogram ABCD

Answer 2

Answer:

I hope it will help you.