construct a parallelogram ABCD such that a b is 4.8 CM BC is 4 cm and diagonal BD is 5.4 CM
amrutha5812:
hi rahul ikadiki ra
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TO CONSTRUCT: A parallelogram ABCD, AB = 4.8 cm, diagonal Bd = 5.4 cm , altitude from A to BC = 4 cm.
STEP 1: Draw a ray AX & cut AL = 4 cm on it.
STEP 2: On AX at point L construct a perpendicular LY
STEP 3: Taking A as centre with 4.8 cm radius draw an arc cutting extended YL at point B. Join A & B.
STEP 4: Now, with same radius 4.8 cm , taking C as centre draw an arc.
STEP 5 : And then taking A as centre , with BC as radius, cut the previous arc at point D.
STEP 6 : Join AD & CD.
ABCD will be the required parallelogram.
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