Question

Construct a parallelogram ABCD such that I(BC)=6.5cm, 1(AB)=4.5cm,m_ABC = 55°.​

Answer 1

Answer:

(1) Draw a sufficiently long line segment using a ruler.

(2) Locate points A and B on it such that AB = 5 cm.

(3) With A as the centre and radius 3.7 cm, draw an arc.

(4) With B as the centre and radius 4.6 cm, draw another arc that cuts the previous arc at C.

(5) Join AC and BC.

Then, ABC is the required triangle.

1) Draw a sufficiently long line segment using a ruler.

(2) Locate points P and Q on it such that PQ = 5.6 cm.

(3) With P as the centre and radius 7 cm, draw an arc.

(4) With Q as the centre and radius 4.5 cm, draw another arc that cuts the previous arc at R.

(5) Join PR and QR.

Then, PQR is the required triangle.

Step-by-step explanation:

I hop this helps you