Math, asked by jagdev01455, 1 month ago

Construct a
parallelogram ABCD, who adjacent
sides AB 2 4.5cm, BC 3.7 cm Height = 2.5 cm. write
steps of construction​

Answers

Answered by jaguarh71
0

Answer:

jdjsn

Step-by-step explanation:

thank for free point

Answered by Ipsitsingharoy
3

Construct the following quadrilaterals:

(i) Quadrilateral ABCD

(ii) Quadrilateral JUMP

AB = 4.5 cm

JU = 3.5 cm

BC = 5.5 cm

UM = 4 cm

AD = 4 cm

MP = 5 cm

AD = 6 cm

PJ = 4.5 cm

AC = 7 cm

PU = 6.5

(iii) Parallelogram MORE

(iv) Rhombus BEST

OR = 6 cm

BE = 4.5 cm

RE = 4.5 cm

ET = 6 cm

EO = 7.5 cm

Sol. (i) First we draw a rough sketch of a quadrilateral ABCD and write down its dimensions as shown. We may divide it into two conveniently constructible Δs ABC and ACD.

Steps of construction:

1. Draw AC = 7 cm.

2. With A as centre and radius 4.5 cm, draw an arc (below AC).

3. With C as centre and radius 5.5 cm, draw another arc cutting the previous arc at B.

4. Join AB and BC

5. With A as centre and radius 6 cm, draw an arc (above AC).

6. With C as centre and radius 4 cm, draw another arc cutting the previous arc and D.

7. Join AD = CD.

Then, ABCD is the required quadrilateral.

(ii) First we draw a rough sketch of a quadrilateral JUMP and write down its dimensions as shown.

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