Question

construct a parallelogram ABCD with AB = 6CM , BC = 5.2cm and angle A = 75 degree ​

Answer 1

$\mathfrak{ \huge{ \tt{question : }}}$

construct a parallelogram ABCD with AB = 6CM , BC = 5.2cm and angle A = 75 degree

$\mathfrak{ \huge{ \green{steps \: of \: contructions : }}}$

Refer the attachment!!

1. Draw AB = 6 cm.
2. Draw angle DAB = 75°
3. Cut DA = 5.2 cm. (opposite angles of parallelogram are equal)
4. From D draw arc of radius 6 cm.
5. From B draw arc of radius 5.2 cm which meets first arc at C.
6. Join CD and CB.

Thus ABCD is the required ||gm.

Answer 2

Answer:

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Step-by-step explanation:

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