Question

construct a parallelogram pqrs given PQ = 8.2 cm and PR = 9.5 cm and QS =10.8 cm​

Answer 1

Answer:

1.draw a line of 8.2 cm PQ

2. with help of compass draw an arc of 9.5 cm PR from Q.

3.with the help of compass draw an arc of 10.8 cm QS (don't intersect them)

4. join P and R

5.join Q and S

6.join R and S

7.parallelogram PQRS is a required triangle

Answer 2

$PQRS$ is the required parallelogram.

Step-by-step explanation:

Given,

Construct a parallelogram $PQRS$ given $PQ = 8.2\ cm,PR = 9.5\ cm\ and\ QS =10.8\ cm$

Following steps:

• Draw a line $PQ=8.2\ cm$ using scale.
• $P$ center and $4.75\ cm$ as radius draw an arc.
• Similarly, $Q$ as center and $5.4\ cm$ as radius draw an arc which cuts the before arc at $O$
• Extend the line $PO$ and $QO$ with same line such that $PO=OR$ and $QO=OS$
• Join $QR,RS\ and\ PS$

Hence, $PQRS$ is the required parallelogram.