Question

construct a parallelogram pqrs in which PQ = 5 cm ,QR= 6 cm and < PQR= 80 degree ​

Answer 1

Construction of a parallelogram PQRS:

• Draw a line segment PQ = 5 cm.

• Draw a ray QX from Q such that ∠PQR = 80°.

• Draw an arc on QX with length 6 cm.

• Name this point as R.

• Now with a radius of 6 cm, draw an arc from P above it.

• Cut this arc from R with radius of 5 cm.

• Name point of intersection of these two arcs as S.

Answer 2

Step-by-step explanation:

• First draw an arc PQ = 5 cm .
• Draw an arc QX from Q such that angle PQR = 80° .
• Draw an arc on QX with length 6 cm , name this point as R .
• Now with a radius of 6 cm , draw an arc from P above it .
• Cut this arc from R with radius of 5 cm .
• Name point of intersection of those arcs as S .
• Hence , a parallelogram PQRS is ready .

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