Question

construct a parallelogram PQRS in which PQ=6.3 cm ,PS=3.8 cm and QS = 7.2 cm.​

Answer 1

$PQRS$ is the required parallelogram.

Step-by-step explanation:

Given,

Construct a parallelogram $PQRS$ in which $PQ=6.3\ cm$,$PS=3.8\ cm$ and $QS=7.2\ cm$

Following steps:

• Draw a line segments $PQ=6.3\ cm$ using scale.
• $P$ as center and $3.8\ cm$ as radius draw an arc also $Q$ as center $7.2\ cm$ as radius draw an arc which cuts the before arc at $S$
• Draw parallel line with $PQ$ through point $S$ like $SX\parallel PQ$
• $Q$ as center and $3.8\ cm$ as radius draw an arc on line $SX$ name as $R$
• Join $PS$ and $QR$

Hence, $PQRS$ is the required parallelogram.

Answer 2

Answer:

construct parallelogram