Construct a parallelogram PQRS in which PQ=6.3cm,PS=3.8 cm and QS=7.2 cm.
Answers
Step-by-step explanation:
1. make a line mark a point p from p draw an Arc of 6.3 cm cutting line at q
2. from p make an Arc upwards of radius 3.8 CM and from q make an Arc upward of radius 7.2cm
3. mark the intersection point of these two arc as s
4. from s draw an arc of 6.3 CM and from q draw an arc of 3.8 CM
5. name the intersection point r
6. join p q r s
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steps of construction:
1. make a line mark a point p from drawn an Arc of 6.3 CM cutting line at q
2. from P make an Arc upwards of radius 3.8 cm and from q make an Arc upward of radius 7.2
3. mark D intersection point of these two arc as S
4. from S draw an Arc of 6.3 cm and from q draw an Arc of 3.8 CM
5. name the intersection point r
6. join P,Q,R,S.