Question

Construct a parallelogram PQRS in which PQ=6.3cm,PS=3.8 cm and QS=7.2 cm.​

Answer 1

Step-by-step explanation:

1. make a line mark a point p from p draw an Arc of 6.3 cm cutting line at q

2. from p make an Arc upwards of radius 3.8 CM and from q make an Arc upward of radius 7.2cm

3. mark the intersection point of these two arc as s

4. from s draw an arc of 6.3 CM and from q draw an arc of 3.8 CM

5. name the intersection point r

6. join p q r s

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Answer 2

steps of construction:

1. make a line mark a point p from drawn an Arc of 6.3 CM cutting line at q

2. from P make an Arc upwards of radius 3.8 cm and from q make an Arc upward of radius 7.2

3. mark D intersection point of these two arc as S

4. from S draw an Arc of 6.3 cm and from q draw an Arc of 3.8 CM

5. name the intersection point r

6. join P,Q,R,S.