Question

construct a parallelogram PQRS in which PQ= 6cm angle Q=120 and angle RPQ= 30

Answer 1

Step-by-step explanation:

Given Construct a parallelogram PQRS in which PQ= 6 cm angle Q = 120 and angle RPQ = 30

• Construct a line segment PQ = 6 cm.
• Construct an angle 120 degree at point Q.
• Construct an angle of 30 degree at point P.
• Both the angles intersect and let the point be marked R.
• So angle QPS + angle PQR = 180 degree
•         Or QPS = 180 – PQR
•                     = 180 – 120
•                     = 60 degree
• So the angle at P is 60 degree and let the point be PM
• So on the line PR construct an angle 30 degree at R and let the point be RN
• So angle SRP = angle QPR = 30 degree (since alternate angles)
• The line PM and RN intersect at a point and let the point be S.
• Therefore PQRS forms a parallelogram.

Reference link will be

https://brainly.in/question/29858882

Answer 2

Step-by-step explanation:

pqrs forms the parallelogram

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