Construct a parallelogram PQRS, in which PR = 6 cm. Q8 = 8 cm and the angle between the two diagonals is 60°
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Both diagonals of parallelogram are given then
- take AC = 8cm
- BD = 6m.
Steps of construction :
- ⇒ Draw a line segment AC = 8cm.
- ⇒ With center A and radius more than half of AC, draw arcs, one on each sides of AC.
- ⇒ With center B and same radius, draw arcs cutting the previous arcs P and Q respectively.
- ⇒ Join PQ which is perpendicular to BC and bisects BC at half.
- ⇒ Construct an angle 60°at O on both sides of AC that is above and below
- ⇒ Then draw the line through an angles which will be passing through pint O.
- ⇒ Cut off OD = 3cm and OB = 3cm. Then we get DB = 6cm.
- ⇒ Join AD, DC, BC and BA.
Thus, ABCD is the required parallelogram.
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