Construct a parallelogram PQRS in which PR =6 cm ,QS = 8 cm and the angle between the two diagonal is 60°
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Answered by
12
Answer:
given PO = 8 cm
therefore PO=OR=8cm
PO+OR=16cm (PR)
given pr=ps+4cm
therefore QS=12cm
os=1/2×12=6cm
ans= 6cm
Answered by
30
7 Step construction for Parallelogram
Step-by-step explanation:
We know that,
One of the properties of Parallelogram -
Using *Diagonals of a parallelogram are bisectors of each other.
Construction Steps for Parallelogram -
1.) Line segment PR = 6 cm is being drawn initially as the first step.
2.) Draw an arc P0 = 3 cm, intersecting PR at O, with center P.
3.) Draw an = 60°
4.) With O center, draw an arc of length 4 cm, intersecting XO at S.
5.) Extend the line XO to make it XY.
6.) Draw an arc of 4 cm length, intersecting YO at Q, from O as center.
7.) Join PQ, QR, RS, and SP.
PQRS is the required Parallelogram
Attachments:
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