Math, asked by Sarangsksarang85091, 1 year ago

Construct a parallelogram PQRS in which PR =6 cm ,QS = 8 cm and the angle between the two diagonal is 60°

Answers

Answered by kirancl
12

Answer:

given PO = 8 cm

therefore PO=OR=8cm

PO+OR=16cm (PR)

given pr=ps+4cm

therefore QS=12cm

os=1/2×12=6cm

ans= 6cm

Answered by dk6060805
30

7 Step construction for Parallelogram

Step-by-step explanation:

We know that,

One of the properties of Parallelogram -

Using *Diagonals of a parallelogram are bisectors of each other.

Construction Steps for Parallelogram -  

1.) Line segment PR = 6 cm is being drawn initially as the first step.

2.) Draw an arc P0 = 3 cm, intersecting PR at O, with center P.

3.) Draw an \angle XOR  = 60°

4.) With O center, draw an arc of length 4 cm, intersecting XO at S.

5.) Extend the line XO to make it XY.

6.) Draw an arc of 4 cm length, intersecting YO at Q, from O as center.

7.) Join PQ, QR, RS, and SP.

PQRS is the required Parallelogram

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