Math, asked by mujtaba121, 2 months ago

Construct a parallelogram PQRS in which QR = 6 cm, PQ = 4 cm and ∠PQR = 60°.
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Answers

Answered by MayurMhadeshwar
0

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Answered by chandan62000
2

Step-by-step explanation:

Firstly,draw a straight line"PQ" of length 4cm then, using protractor draw angle PQR= 60° and extend it to in such a manner that lin segment QR measures 6 cm. Now, from the line segment QR draw an angel QSR=120°[ since, adjacent angles of a parallelogram are Supplementary].and extend it to point S such that length of RS is 4cm[ opposite sides of a parallelogram are equal] .At last,join point S to P such that it measures 6 cm.

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