Math, asked by sachumore1977, 1 month ago

Construct a parallelogram PQRS such that l(PQ) = 6•2 cm

Measure of angle PQR = 65⁰, l(QR) = 5•1 cm​

Answers

Answered by Anonymous
10

hope this is helpful for you

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Answered by adityakothalikar
5

Answer:

Construct the following quadrilaterals of given measures.

(1) In ☐ MORE, l(MO) = 5.8 cm, l(OR) = 4.4 cm, m∠M = 58°, m∠O = 105°, m∠R = 90°.

(2) Construct ☐ DEFG such that l(DE) = 4.5 cm, l(EF) = 6.5 cm, l(DG) = 5.5 cm, l(DF) = 7.2 cm, l(EG) = 7.8 cm.

(3) In ☐ ABCD l(AB) = 6.4 cm, l(BC) = 4.8 cm, m∠A = 70°, m∠B = 50°, m∠C = 140°.

(4) Construct ☐ LMNO such that l(LM) = l(LO) = 6 cm, l(ON) = l(NM) = 4.5 cm, l(OM) = 7.5 cm.

ANSWER:

(1)

Steps of Construction:

Step 1: Draw MO = 5.8 cm.

Step 2: Draw ∠MOX = 105°.

Step 3: With O as centre and radius 4.4 cm, draw an arc cutting ray OX at R.

Step 4: Draw ∠ORY = 90°.

Step 5: Draw ∠OMZ = 58° such that ray MZ and ray RY intersect each other at E.

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