Construct a parallelogram PQRS whose side PQ=6cm and it’s two diagonals are 7.5 cm and 8.5 cm
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Answer:
Hence we have constructed a parallelogram PQRS with the given measurements
Step-by-step explanation:
Given that a parallelogram PQRS whose side PQ=6cm and it’s two diagonals are 7.5 cm and 8.5 cm
Let PR and QS be the diagonals of 7.5 cm and 8.5 cm respectively
To construct a parallelogram PQRS :
- With the given measurements we can construct a parallelogram.
- Draw a parallelogram PQRS and draw a diagonal from P to R and another diagonal from Q to S.
- Now mark the ,measurements
- Hence we have constructed a parallelogram PQRS refer figure.
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We know that, sides of rhombus are equal.
So, PQ=QR=RS=PS=6cm
⇒ Draw a line segment PQ=6cm
⇒ Take P as center with radius 8cm and draw an arc.
⇒ Take Q as center with radius 6cm and draw an arc, which meets previous arc at point R.
⇒ Take P as center with radius 6cm and draw an arc.
⇒ Take R as center with radius 6cm and draw an arc, which meets previous arc at point S.
⇒ Join QR,RS,SP,PR and QS
∴ PQRS is a required rhombus.
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