Question

construct a parallelogram PQRS with PQ = 4 cm and, QR = 5.5 cm and Angel P = 70°​

Answer 1

Answer:

Construct it with angle Q = 70°(external angle) and take PS = 5.5 cm

Step-by-step explanation:

STEPS OF CONSTRUCTION

1. Draw PQ = 4cm.

2. With any radius and points P and Q as centres construct 70° angles from each.[Since PS and QR need to be parallel the angle at which they will be incident to the line PQ should be equal. NOTE: From point Q the angle 70° should be external and not internal]

3. With a radius of 5.5 cm and Q as centre cut and arc in the line m which is incident at 70°[external angle] to the point Q and mark the new point as R.

4. Since opposite sides are equal in a //gm, contruct the same 5.5 cm arc at line l from point P.

5. Join R and S.

6. PQRS is the required Parallelogram.

It will be found that RS = PQ = 4cm