Construct a parallelogram where two diagonals are of length 6cm and 4.6 cm and the included angle between them is 60°.
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Construction of a parallelogram
Explanation:
Given: Parallelogram ABCD with diagonals of length 6cm and 4.6cm and the included angle between them is 60°.
Construction:
- Let AC and BD be the diagonals and O be the point of their intersection.
- Draw a line segment AC = 6 cm.
- Mark the midpoint of AC at 3cm and name it O.
- At O, mark an angle of 60° and extend the arm of the angle on both sides of the line AC.
- With O as centre and half of BD (4.6 / 2 = 2.3 cm) as radius, draw two arcs cutting the arm of the angle on eithe side of AC.
- Mark the points as B and D.
- Join AB, BC, CD and DA.
- ABCD is the required parallelogram.
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