Math, asked by madhy82, 1 year ago

construct a parallelogram whose one side is 6.2cm and whose diagonals are 7cm and 7.6cm​

Answers

Answered by shashank323
32

IS THIS HELPFULL TO U

Step-by-step explanation:

step1=draw a diagonals AC 7.2 cm

step2=make the bisect of the line AC because it is a parallelogram whose diagonals are bisect

step3=the line which bisect the diagonals from point o make the half of 7 that is 3.5 cm and cut from o on dotted line bot up and down

step4=extent the cut of 3.5 cm

step5=from A measure6.2 cm side than cut at the extented cut of 3.5 cm down

step6= again from c cut to up

step 7 =match the cut arc

step8=the parlleogram is ready

THERE IS NO MISTAKE IN FIGURE THAT IS 7.6 CM ONLY I HAVE WRITTEN WRONG OK MAKE IT CORRECT

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Answered by verma1085
19

guys this is the correct and easiest answer

I am explaining by step by step:-

step 1- Draw a base line segment AB =6.2 cm (given)

step 2- with a as centre draw an arc of 3.5cm ( half of 7cm ) at point O

step 3- with b as centre draw an arc of 3.8 cm ( half of 7.6 cm ) intersects the privious arc.

step 4- draw a line as long as you want from D to B AND A TO C

step 5- with o as centre draw an arc of 3.5 cm at point C

step -6 with o as centre draw an arc of 3.8 cm at point D .

step 6- join A to c and B to c and A to d and D to c

Thus we get the required parallelogram ABCD

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