construct a parallelogram whose one side is 6.2cm and whose diagonals are 7cm and 7.6cm
Answers
IS THIS HELPFULL TO U
Step-by-step explanation:
step1=draw a diagonals AC 7.2 cm
step2=make the bisect of the line AC because it is a parallelogram whose diagonals are bisect
step3=the line which bisect the diagonals from point o make the half of 7 that is 3.5 cm and cut from o on dotted line bot up and down
step4=extent the cut of 3.5 cm
step5=from A measure6.2 cm side than cut at the extented cut of 3.5 cm down
step6= again from c cut to up
step 7 =match the cut arc
step8=the parlleogram is ready
THERE IS NO MISTAKE IN FIGURE THAT IS 7.6 CM ONLY I HAVE WRITTEN WRONG OK MAKE IT CORRECT
![](https://hi-static.z-dn.net/files/d5f/ed552ebb9a9b4f5585df17298ae153bf.jpg)
guys this is the correct and easiest answer
I am explaining by step by step:-
step 1- Draw a base line segment AB =6.2 cm (given)
step 2- with a as centre draw an arc of 3.5cm ( half of 7cm ) at point O
step 3- with b as centre draw an arc of 3.8 cm ( half of 7.6 cm ) intersects the privious arc.
step 4- draw a line as long as you want from D to B AND A TO C
step 5- with o as centre draw an arc of 3.5 cm at point C
step -6 with o as centre draw an arc of 3.8 cm at point D .
step 6- join A to c and B to c and A to d and D to c
Thus we get the required parallelogram ABCD
![](https://hi-static.z-dn.net/files/dea/9f7e1a353abfcacdb06a3d602c3b3746.jpg)