Question

construct a parllelogram pqrs pq=4.5 QR=3cm<pqr=60​

Answer 1

1. Draw a line segment PQ = 4.5 cm

2. Take a compass and keeping Q as a centre construct an angle of 60 degrees.

3. Now take the radius of 3 cm, draw an arc on the 60-degree angle line. The intersection point of the 3 cm arc and 6 degrees will be R.

4. As per the supplementary property of a parallelogram, SPQ + PQR = 180. Hence draw an angle of 120 degrees on point P.

5. Now draw an arc of 3 cm and mark it as S

6. Join PQRS to form a parallelogram.

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