Question

construct a perpendicular bisector of the line EF=8.5cm​

Answer 1

Answer

Steps to follow

Draw a line segment with scale 8.5cm.

Mark end points as P and Q

From point P draw arcs below and above the line PQ.

From point Q draw arcs below and above the line PQ with same distance.

Draw a line perpendicular to line PQ where the arcs cut.

Mark a point X where the arcs cut each other.

Steps of Construction :

1. With P and Q as centers, draw arcs on both sides of PQ with equal radii. The radius should be more than half the length of PQ.

2. Let these arcs cut each other at points R and RS

3. Join RS which cuts PQ at D. Then RS=PQ. Also ∠POR=90

∘

.

Hence, the line segment RS is the perpendicular bisector of PQ as it bisects PQ at P and is also perpendicular to PQ. On measuring the lengths of PR=4cm, QR=4 cm Since PR=QR, both are 4cm each

∴PR=QR.

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