construct a perpendicular line biesector of AB = 8cm
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-Draw a line AB = 8 cm.
-Taking A as a centre and radius more than half of length AB, draw two arcs in upper and lower portion of AB.
-Taking B as a centre and same radius, draw two arcs which cut the previous arcs at E and F.
-Join EF which cut AB at C.
-EF is the required perpendicular bisector of AB.
-Measuring AC and CB, each is equal to 4cm.
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