Question

construct a polynomial whose zero are 1 and -3 verify the relation between the cofficent and zeroes of the polynomial​

Answer 1

Answer:

sum of zeros = 1 +(-3) = 1-3 =-2

product of zeros = 1×(-3) = -3

polynomial = (x^2 +2 -3)

sum of zeros = -b/a

-2 = -2/1

-2=-2

product of zeros = c/a

-3 = -3/1

-3 = -3

Answer 2

Step-by-step explanation:

k( x2 - sx + p)

s= 1+(-3)

s= 1-3=-2

p=1×(-3)

p= -3

k[x2 - (-2)x +(-3)]

1(x2+2x-3)

1x2+2x-3