Construct a PQR given PQ= 7 cm,
angle.Answers
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Answer:
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1.Draw base BC=7cm
2.Let's draw ∠B=75
∘
.Let the ray be BX
3.Open the compass to length AB+AC=13cm.From point B as center, cut an arc on ray BX.Let the arc intersect BX at D
4.Join $$CD$
5.Now, we will draw perpendicular bisector of CD
6.Mark point A where perpendicular bisector intersects BD
7.Join AC
Result:△ABC is the required triangle.
solution
Answered by
0
Step-by-step explanation:
sol:-
x+7=180
x=180-7
x=173
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