Question

Construct a∆ PQR given that QR=7cm, LPQR = 45° and QP-PR = 2cm

Answer 1

Answer:

let PR be x

by Pythagoras theorem

we know that

angle PQR is 45°

then angle QRP is 90°

so,

QP2=QR2+RP2

put the values

give(2+x)2=7*7+x2

by formula ,

4+x2+2*2*x=49+x2

x square cut from x square

4+4x=49

4x=49-4

x=45/4