Question

construct a pqr having perimeter 12cm and angle of triangle are in the ratio 3:4:5.

Answer 1

Answer:

Step-by-step explanation:

Steps of Construction:

Draw B'C' = 13 cm

Then divide , B'C' in the ratio 3:4:5

B'B : BC : CC' = 3:4:5 ( by similarity of triangles)

Now, construct AB = B'B

Construct AC = CC'

Hence AB: BC : AC = 3:4:5

Hence , Triangle ABC is the required triangle.

Here, AB = 13/4 cm, BC = 13/3 cm & AC = 65/12 cm

How to divide a line segment in given ratio: i've explained below

Draw a ray B'P5 as shown above. Starting from B' with same radius , mark 12 points on the ray. I named 3rd point as P3, 7th point as P4 & 12th point as P5. Join P5C' & then construct lines // to P5C', from P4 & P3 . So now the ray & segment B'C'have been divided in the ratio 3:4:5

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