Construct a ∆PQR if PQ = 5 cm, ∟PQR = 1050
and ∟QRP = 400
please reply fast now my exam is going on only half an hour is left please hepl me
Answers
Answered by
2
Answer:
PQR +QRP+RPQ=180
105+ 40+ RPQ=180
145+ RPQ=180
RPQ= 180-145
RPQ= 35
LET DRAW A LINE PQ = 5CM
DRAW ANGLE P = 35°
DRAW ANGLE Q = 105°
FINALLY THEY INTERSECT EACH OTHER AT POINT R= 40
Similar questions