Math, asked by gurpreet9884, 2 months ago

Construct a ∆PQR if PQ = 5 cm, ∟PQR = 1050

and ∟QRP = 400

please reply fast now my exam is going on only half an hour is left please hepl me

Answers

Answered by sanjudnath
2

Answer:

PQR +QRP+RPQ=180

105+ 40+ RPQ=180

145+ RPQ=180

RPQ= 180-145

RPQ= 35

LET DRAW A LINE PQ = 5CM

DRAW ANGLE P = 35°

DRAW ANGLE Q = 105°

FINALLY THEY INTERSECT EACH OTHER AT POINT R= 40

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