Question

construct a ∆PQR in which ∆P=70° , ∆Q=80° and PR = 5.6cm​

Answer 1

Answer:

1: Draw a line segment AB (PQ+QR+PR=9.5 cm ) = 9.5cm.

2: Draw an angle of 70° at A and an angle of 80° at B.

3: Bisect ZA and B. Let the bisectors of ZA and B intersect in P.

4: Draw perpendicular bisector DE of AP which intersect AB in Q and FG of AB which intersect AB in R.

5: Join PQ and PR.

∆PQR is the required triangle.

Answer 2

Answer:

sorry

Step-by-step explanation:

i not understand